Solve the following pair of linear equations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given equations are:$1) \, 2x + 3y = 7$$2) \, 6x + 9y = 23$Check the ratio of coefficients:$\frac{a_1}{a_2} = \frac{2}{6} = \frac{1}{3}$$\frac{b_1

Vedclass · Accepted Answer

$	ext{No solution } (\varnothing)$

Vedclass · Answer

(B) Given equations are:$1) \, 2x + 3y = 7$$2) \, 6x + 9y = 23$Check the ratio of coefficients:$\frac{a_1}{a_2} = \frac{2}{6} = \frac{1}{3}$$\frac{b_1}{b_2} = \frac{3}{9} = \frac{1}{3}$$\frac{c_1}{c_2} = \frac{7}{23}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel to each other.Therefore,the system of equations has no solution,denoted by $\varnothing$.

Solve the following pair of linear equations by the method of substitution: $2x + 3y = 7$ and $6x + 9y = 23$.

Similar Questions

For the linear equation in two variables $2x - 5y = 3$,if $y = -1$,then $x = \ldots$

If $2x + y = 35$ and $3x + 4y = 65$,then find $\frac{x}{y}$.

Solve the following pair of linear equations by the substitution method.
$0.2 x + 0.3 y = 1.3$
$0.4 x + 0.5 y = 2.3$

Form the pair of linear equations for the following problem and find their solution by the substitution method.
The larger of two supplementary angles exceeds the smaller by $18^{\circ}$. Find the angles.

If $y = \frac{1}{2} x$ and $x + 2y = 8$,then $x = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module